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Divisibility Rules Ways to determine if one number can evenly be divided by another, without actually dividing them. Number Rule Example Divisible? 2 The last digit is even: (0,2,4,6,8). 5 7 6 is even YES 8 3 1 is not even NO 5 3 7 --- 5+3+7 = 15, YES 3 The sum of the digits is divisible by 3. 15 %u00f7 3 = 5 8 3 3 --- 8+3+3 = 14,14 %u00f7 3 has a remainder NO Double the tens digit and 2 5 7 6 --- 2 x 7 + 6 = 20, YES 4 add to the ones digit. This answer is divisible 20 %u00f7 4 = 5 2 5 2 5 --- 2 x 2 + 5 = 9, by 4. 9 %u00f7 4 has a remainder NO 5 The last digit is 0 or 5. 3 8 5 last digit is 5 YES 9 6 4 last digit is 4 NO 4 3 2 --- even; YES 6 The number is divisible 4+3+2 = 9 and 9 %u00f7 3 = 3 5 2 4 --- even; by both 2 and 3. 5+2+4 = 11 and 11 %u00f7 3 has a remainder NO Double the last digit and 5 8 1 --- 2 x 1 = 2, subtract it from the 58 - 2 = 56 YES rest of the number. and 56 %u00f7 7 = 8 7 This answer is 0 or divisible by 7. 3 2 1 --- 2 x 1 = 2 * You can apply this rule 32 - 2 = 30 and 30 %u00f7 7 NO to that answer again. has a remainder Fall 2017